一:求学霸,下列概率论与数理统计矩估计练习题的答案
用分部积分法求积分
二:矩估计的题目,求解答!
E(x)=0*θ^2+1*2θ(1-θ)+2*(1-θ)^2=2-2θ
X(—)=(0*n1+1*n2+2*n3)/(n1+n2+n3)=(n2+2n3)/(n1+n2+n3)
令E(x)=X(—)求得θ=(2n1+n2)/[2(n1+n2+n3)]
用分部积分法求积分
E(x)=0*θ^2+1*2θ(1-θ)+2*(1-θ)^2=2-2θ
X(—)=(0*n1+1*n2+2*n3)/(n1+n2+n3)=(n2+2n3)/(n1+n2+n3)
令E(x)=X(—)求得θ=(2n1+n2)/[2(n1+n2+n3)]